Fix code style (#4356)

pull/4402/head
Mikhail Ostashchenko 1 year ago committed by GitHub
parent ce41b3a955
commit 1ec6005fe1
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  1. 14
      src/data/roadmaps/cpp/content/107-structures-and-classes/102-multiple-inheritance/100-diamond-inheritance.md

@ -7,39 +7,37 @@ To resolve this ambiguity, you can use virtual inheritance. A virtual base class
*Example:* *Example:*
```cpp ```cpp
#include<iostream> #include <iostream>
using namespace std;
class Base { class Base {
public: public:
void print() { void print() {
cout << "Base class" << endl; std::cout << "Base class" << std::endl;
} }
}; };
class Derived1 : virtual public Base { class Derived1 : virtual public Base {
public: public:
void derived1Print() { void derived1Print() {
cout << "Derived1 class" << endl; std::cout << "Derived1 class" << std::endl;
} }
}; };
class Derived2 : virtual public Base { class Derived2 : virtual public Base {
public: public:
void derived2Print() { void derived2Print() {
cout << "Derived2 class" << endl; std::cout << "Derived2 class" << std::endl;
} }
}; };
class Derived3 : public Derived1, public Derived2 { class Derived3 : public Derived1, public Derived2 {
public: public:
void derived3Print() { void derived3Print() {
cout << "Derived3 class" << endl; std::cout << "Derived3 class" << std::endl;
} }
}; };
int main() int main() {
{
Derived3 d3; Derived3 d3;
d3.print(); // Now, there is no ambiguity in calling the base class function d3.print(); // Now, there is no ambiguity in calling the base class function
d3.derived1Print(); d3.derived1Print();

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